x^2-50x-432=0

Solution for x^2-50x-432=0 equation:

x^2-50x-432=0

a = 1; b = -50; c = -432;
Δ = b2-4ac
Δ = -502-4·1·(-432)
Δ = 4228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4228}=\sqrt{4*1057}=\sqrt{4}*\sqrt{1057}=2\sqrt{1057}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{1057}}{2*1}=\frac{50-2\sqrt{1057}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{1057}}{2*1}=\frac{50+2\sqrt{1057}}{2}
$